Quantcast
Channel: blog化学
Viewing all articles
Browse latest Browse all 2255

Newton/Julia Fractals (2059)~(2070)

$
0
0
Newton/Julia Fractal (2059)

f(z) = (z^2-1)*(z-(-1.003+3.001*i))/(1-conj(-1.003+3.001*i)*z)    
イメージ 2

    
Newton/Julia Fractals (2060)

f(z) = (z^2-1/10)*(z-(-1.003+3.001*i))/(1-conj(-1.003+3.001*i)*z) 
イメージ 1

   Newton/Julia Fractals (2061)

f(z) = (z^3-1/10)*(z-(-1.003+3.001*i))/(1-conj(-1.003+3.001*i)*z) 
イメージ 3

   
  Newton/Julia Fractals (2062)

f(z) = (z^3)*(z-(-1.003+3.001*i))/(1-conj(-1.003+3.001*i)*z)     
イメージ 4

  Newton/Julia Fractals (2063)

f(z) = (z^3+z^2/5-1/10)*(z-(-1.003+3.001*i))/(1-conj(-1.003+3.001*i)*z)  
イメージ 5


  Newton/Julia Fractals (2064)

f(z) = z^3+1.02*(1.15*i)*EXP(0.1*i)*z
イメージ 6

       
 Newton/Julia Fractals (2064-b)

f(z) = z^3+1.02*(1.20*i)*EXP(0.1*i)*z
イメージ 7
Newton/Julia Fractals (2064-c)

f(z) = z^3+1.02*(1.16*i)*EXP(0.1*i)*z
イメージ 8


Newton/Julia Fractals (2064-d)

f(z) = z^3+1.02*(1.18*i)*EXP(0.01*i)*z
イメージ 9



Newton/Julia Fractals (2064-e)

f(z) = z^3+1.02*(1.18*i)*EXP(0.11*i)*z
イメージ 10



Newton/Julia Fractals (2065)

f(z) = z^3+1.02*(-1.1153+.50386*i)*EXP(0.11*i)*z
イメージ 11

       
Newton/Julia Fractals (2066)

f(z) = z^3+1.02*(-1.1053+.50386*i)*EXP(0.11*i)*z 
イメージ 12

      
Newton/Julia Fractals (2067)

f(z) = z^3+1.02*(-.98311-.23200*i)*EXP(0.11*i)*z
イメージ 13


Newton/Julia Fractals (2068)

f(z) = z^3+1.02*(-.96311-.23200*i)*EXP(0.11*i)*z
イメージ 14



Newton/Julia Fractals (2069)

f(z) = z^3+1.02*(-.947766-.333964*i)*EXP(0.11*i)*z
イメージ 15

       
Newton/Julia Fractals (2070)

f(z) = z^3+(1.15*i)*EXP(-.10355+.15967*i)*z
イメージ 16



Viewing all articles
Browse latest Browse all 2255

Trending Articles