Quantcast
Channel: blog化学
Viewing all articles
Browse latest Browse all 2255

Newton/Julia Fractals (2214)~(2225)

$
0
0
Newton/Julia Fractal (2214)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*Re(z^2)+z+1)
イメージ 1

    
Newton/Julia Fractal (2215)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*z*Re(z)+z+1)
イメージ 2

    
Newton/Julia Fractal (2216)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*(Re(z)-Im(z)*i)^2+z+1)
イメージ 3

    
Newton/Julia Fractal (2217)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*(Re(z)-Im(z)*i)*z+z+1)
イメージ 4

    
Newton/Julia Fractal (2218)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*(Re(z)*i-Im(z))*z+z+1)
イメージ 5

    
Newton/Julia Fractal (2219)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*(ABS(Re(z))-Im(z)*i)*z+z+1)
イメージ 6

    
Newton/Julia Fractal (2220)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*(ABS(Re(z))+Im(z)*i)*z+z+1)
イメージ 7

    

Newton/Julia Fractal (2221)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*(SGN(Re(z))+Im(z))^2+z+1)
イメージ 8

    
Newton/Julia Fractal (2222)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*(Arg(z))^2+z+1)
イメージ 9

    
Sonate K4286
イメージ 10



Sonate K4287
イメージ 11




Newton/Julia Fractal (2223)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*Arg(z^2)+z+1)
イメージ 12

    

Newton/Julia Fractal (2224)

f(z) = z-(4*z*(z+1)^4+z^3-3*(z+1))/(25*Im(z^2)+z+1)
イメージ 13

    

Newton/Julia Fractal (2225)

f(z) = z-(z^4+z^3+z^2+z+1)/(5/3*z^325*Arg(z^2)+11*z+1)
イメージ 14

    


Viewing all articles
Browse latest Browse all 2255

Trending Articles