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Newton/Julia Fractals (240)~(249)

Newton/Julia Fractal (240)
 
f(z) = z- (z^4/50-z^3/2.5+3*z^2-1)/(4*z^3/50-3*z^2/10+3*z)
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BS13
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Sonate BS14
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Sonate BS15
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Newton/Julia Fractal (241)
 
f(z) = z- (z^4/50-z^3/2.3+3*z^2-1)/(4*z^3/50-3*z^2/10+3*z)
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Sonate BS17
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Sonate BS18
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Sonate BS19
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Newton/Julia Fractal (241)
 
f(z) = z- (z^4/50-z^3/2+2.9*z^2-1)/(4*z^3/50-3*z^2/10+3*z)
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Sonate BS21
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Sonate BS22 Cross
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Newton/Julia Fractal (242)
 
f(z) = z- (z^4/50-z^3/2+2.98*z^2-1)/(4*z^3/50-3*z^2/10+3*z)
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Sonate BS24
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 Sonate BS25
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Newton/Julia Fractal (243)
 
f(z) = z- (z^4/50-z^3/2+3*z^2-1/2)/(4*z^3/50-3*z^2/10+3*z)
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Sonate BS28
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Sonate BS29
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Newton/Julia Fractal (244)
 
f(z) = z- (z^4/50-z^3/2+3*z^2-1/1.5)/(4*z^3/50-3*z^2/10+3*z)
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Sonate BS31
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Newton/Julia Fractal (245)
 
f(z) = z- (z^4/50-z^3/2+3*z^2-1/3)/(4*z^3/50-3*z^2/10+3*z)
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イメージ 20
 
 
Sonate BS33
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Newton/Julia Fractal (246)
 
f(z) = z- (z^4/50-z^3/2+3*z^2-1/4)/(4*z^3/50-3*z^2/10+3*z)
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Sonate BS35
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Newton/Julia Fractal (247)
 
f(z) = z- (z^4/45-z^3/2+3*z^2-1)/(4*z^3/50-3*z^2/10+3*z)
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Sonata BS35 Answer Me
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Newton/Julia Fractal (248)
 
f(z) = z- (z^4/30-z^3/2+3*z^2-1)/(4*z^3/50-3*z^2/10+3*z)
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イメージ 26
 
 
Sonata BS39
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Newton/Julia Fractal (249)
 
f(z) = z- (z^4/20-z^3/2+3*z^2-1)/(4*z^3/50-3*z^2/10+3*z)
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イメージ 28
 
 
Sonate BS41
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イメージ 29
 
 
 

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